Testing a number to see if it's even.

VP	(Posted 2005) [#1]

Is there a better way to return True or False for even-ness than:

iseven% = (num% Shr 1)-((num%+1) Shr 1)

In a context where num% may be MilliSecs()/1000 (to create flashing text, for instance)?

big10p

(Posted 2005) [#2]

is_odd% = num% And 1

or:

is_even% = Not(num% And 1)

VP	(Posted 2005) [#3]

That would be the logical, rather than mathematical solution.

Thanks biggie :D

octothorpe

(Posted 2005) [#4]

The mathematical solution (which would be slower than the bitwise solution given above) would use the MOD operator.

function is_even(num%)
	if (num MOD 2 = 0) then return true else return false
end function