I want to create a zip from an input dir. How?

BlitzMax Forums/BlitzMax Programming/I want to create a zip from an input dir. How?

Pineapple

(Posted 2015) [#1]

Whether it's using a module or a way to run a batch command isn't important, but I need to be able to specify things like encryption and only adding files newer than some date.

degac

(Posted 2015) [#2]

There is a module (gman.zipengine) that allow to create and read .zip files.
You can also specify a password for it.

[http://www.blitzbasic.com/Community/posts.php?topic=82005]

in that thread your should find the forum/website to download the module.

Adding/removing files based on date check, is another history: you need to handle it using FileTime.

Grisu

(Posted 2015) [#3]

Here's a direct link to GMan's forum: http://www.gprogs.com/viewforum.php?id=8

Hardcoal

(Posted 2015) [#4]

I used this plugin and it works fine

Phil Newton

(Posted 2015) [#5]

I also recommend the gman.zipengine extension. I've used it in a few projects and it's very helpful. Creating a zip goes something like this:

' Setup
Local outputFile:String = "myzip.zip"
Local filesToPack:String[] = ["file1.txt", "file2.txt"]

' Create the output
Local zipOut:Byte Ptr = zipOpen(outputFile, APPEND_STATUS_CREATE)

' Add each file
For local file:String = eachin filesToPack

    ' Read file contents into a bank
    Local fileIn:TStream = OpenFile(file)
    Local inSize:Int = StreamSize(fileIn)
    Local inData:TBank = TBank.Create(inSize)
    
    ReadBank(inData, fileIn, 0, inSize)
    
    fileIn.Close()
    
    ' Add the data to the zip
    zipOpenNewFileInZip(zipOut, fileName, Null, Null, Null, Null, Null, Null, Z_DEFLATED, 5)
    zipWriteInFileInZip(zipOut, inData.buf(), inSize)

Next

zipClose(zipOut, outputFile)