Studying C + +
Community Forums/General Help/Studying C + +
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 These days I've ridden a mechanical bull doing an online course in C + + level 1, if but for a person like me who do not finish primary school, have problems. I show them my grades, I do not know if it is easy or that but it goes well. x = 3 + 4 * (8 * ( 4 – ( 9 + 3 ) / 6 ) ); In this case the compiled C + +, the variable takes the value of 67, but I support my answer and I can not understand how this is done. Is to first solve () internally in your order out, but I get lost somewhere. Appreciate your help please. |
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| It's because of precedence of operators. For example, * and / have a higher precedence than - and + so are executed first. The calculations don't simply go from left to right. |
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3 + 4 * (8 * ( 4 – ( 9 + 3 ) / 6 ) 3 +4 * (8 *(4-12)/6) 3 +4 * (8 *(4-2)) 3 +4 * (8 *2) 3 +4 *16 3 +64 = 67 If I pass the course c + + level 1 will be very happy, this is crazy. |
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| Don't they teach BODMAS any more? http://www.mathsisfun.com/operation-order-bodmas.html |
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| BODMAS seems a bit of an obfuscated way... I learned that as PEMDAS. Parentheses (since, as I understand it, brackets are the { and } ones, or the [ and ] set), Exponents, Multiplication, Division, Addition, Subtraction. Memory hook for PEMDAS: "Please Excuse My Dear Aunt Sally." Seems silly, I know, but I remember PEMDAS, whereas BODMAS will probably have escaped my mind by tomorrow, if that. XD |
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